tolong jawab pake cara! 1. 10(2y-10) 2. 2(x+2y-3) 3. (x+5) (5x-1) 4. (x+3) (x-2) 5. (7+2x) (2x-7)

Mapel : Matematika
Bab : Aljabar

1) 10 (2y - 10)
   = 10 x (2y) + 10 x (-10)
   = 20y - 100

2) 2 (x + 2y - 3)
   = 2 x (x) + 2 x (2y) + 2 (-3)
   = 2x + 4y - 6

3) (x + 5 ) (5x - 1)
   = x (5x - 1) + 5 (5x - 1)
   = 5x² - x + 25x - 5
   = 5x² + 24x - 5

4) (x + 3) (x - 2)
   = x (x - 2) + 3 (x - 2)
   = x² - 2x + 3x - 6
   = x² + x - 6

5) (7 + 2x) (2x - 7)
   = 7 (2x - 7) + 2x (2x - 7 )
   = 14x - 49 + 4x² - 14x
   = 4x² + 14x - 14x - 49
   = 4x² - 49

1. (10×2y)-(10×10)=20y-100

2. (2×x)+(2×2y)-(2×3)
=2x+4y-6

3. x(5x+1)+5(5x-1)
5x²+x+25x-5
=5x²+26x-5

4. = x (x-2)+3(x-2)
=x²-2x+3x-6
=x²+x-6

5. 7(2x-7)+2x(2x-7)
=14x-49+4x²-14x
=4x²-49