hitunglah hambatan penggantinya. Secepatnya ya.
Fisika
walidatulanhar
Pertanyaan
hitunglah hambatan penggantinya. Secepatnya ya.
1 Jawaban
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1. Jawaban arwawinar
◆ Hambatan Pengganti Seri 1
[tex] Rs_1 [/tex] = [tex] R_2 [/tex] + [tex] R_3 [/tex]
[tex] Rs_1 [/tex] = 1 ohm + 3 ohm
[tex] Rs_1 [/tex] = 4 ohm
◆ Hambatan Pengganti Seri 2
[tex] Rs_2 [/tex] = [tex] Rs_5 [/tex] + [tex] Rs_6 [/tex]
[tex] Rs_2 [/tex] = 2 ohm + 4 ohm
[tex] Rs_2 [/tex] = 6 ohm
◆ Hambatan Pengganti Parallel
[tex] \frac{1}{R_p} [/tex] = [tex] \frac{1}{Rs_1} [/tex] + [tex] \frac{1}{Rs_2} [/tex] + [tex] \frac{1}{R_4} [/tex]
[tex] \frac{1}{R_p} [/tex] = [tex] \frac{1}{4} [/tex] + [tex] \frac{1}{6} [/tex] + [tex] \frac{1}{12} [/tex]
[tex] \frac{1}{R_p} [/tex] = [tex] \frac{3}{12} [/tex] + [tex] \frac{2}{12} [/tex] + [tex] \frac{1}{12} [/tex]
[tex] \frac{1}{R_p} [/tex] = [tex] \frac{6}{12} [/tex]
[tex] 6R_p [/tex] = 12 x 1
[tex] R_p [/tex] = [tex] \frac{12}{6} [/tex]
[tex] R_p [/tex] = 2 ohm
Hambatan Pengganti Seri 3
[tex] R_s_3 [/tex] = 3 ohm + 2 ohm + 5 ohm
[tex] R_s_3 [/tex] = 10 ohm
Jadi hambatan penggantinya 10 ohm