Fisika

Pertanyaan

hitunglah hambatan penggantinya. Secepatnya ya.
hitunglah hambatan penggantinya. Secepatnya ya.

1 Jawaban

  • ◆ Hambatan Pengganti Seri 1

    [tex] Rs_1 [/tex] = [tex] R_2 [/tex] + [tex] R_3 [/tex]

    [tex] Rs_1 [/tex] = 1 ohm + 3 ohm

    [tex] Rs_1 [/tex] = 4 ohm

    ◆ Hambatan Pengganti Seri 2

    [tex] Rs_2 [/tex] = [tex] Rs_5 [/tex] + [tex] Rs_6 [/tex]

    [tex] Rs_2 [/tex] = 2 ohm + 4 ohm

    [tex] Rs_2 [/tex] = 6 ohm

    ◆ Hambatan Pengganti Parallel

    [tex] \frac{1}{R_p} [/tex] = [tex] \frac{1}{Rs_1} [/tex] + [tex] \frac{1}{Rs_2} [/tex] + [tex] \frac{1}{R_4} [/tex]

    [tex] \frac{1}{R_p} [/tex] = [tex] \frac{1}{4} [/tex] + [tex] \frac{1}{6} [/tex] + [tex] \frac{1}{12} [/tex]

    [tex] \frac{1}{R_p} [/tex] = [tex] \frac{3}{12} [/tex] + [tex] \frac{2}{12} [/tex] + [tex] \frac{1}{12} [/tex]

    [tex] \frac{1}{R_p} [/tex] = [tex] \frac{6}{12} [/tex]

    [tex] 6R_p [/tex] = 12 x 1

    [tex] R_p [/tex] = [tex] \frac{12}{6} [/tex]

    [tex] R_p [/tex] = 2 ohm

    Hambatan Pengganti Seri 3

    [tex] R_s_3 [/tex] = 3 ohm + 2 ohm + 5 ohm

    [tex] R_s_3 [/tex] = 10 ohm

    Jadi hambatan penggantinya 10 ohm