diketahui rumus fungsi f(x) =6 + ax.jika f(a)=a²-2a,bilai f(-a)=

jawab

f(x) = 6 + ax
f(a) = 6 + a(a) = 6 + a² ...(i)
f(a) = a² - 2a ..(ii)

(i) = (ii)
6 + a² = a² -2a
6 = - 2a
a = -3

f(x) = 6 - 3x
f(-a) =6 - 3(-a) = 6 + 3a