jika f(x²+1)=²logx + 1, nilai f(17) + f (5) =

jawab

f(x²+1)= ²logx + 1
x² + 1= 17
x² = 16
x = 4
f(17)= ²log 4 + 1 = ²log 2² + 1 = 2 + 1= 3

x² +1= 5
x² = 4
x  = 2
f(5) = ²log 2 + 1 = 1 + 1= 2

f(17)+ f(5) =  3 + 2 = 5