Lingkaran (x-5)²+(y+1)²=13 memotong garis y=x-1 di titik...

jawab

y = x - 1  , substitusikan ke  (x-5)² +(y+1)² = 13
(x -5)² + (x-1+1)² = 13
x² -10x + 25 + x² - 13 = 0
2x² -10x + 12= 0
x² - 5x + 6 = 0
(x - 3)(x - 2) =0
x= 3  atau x = 2

y = x- 1
x = 3, y = 2 → A(x,y) = (3,2)
x = 2 , y = 1 →B(x,y) = (2,1)