Matematika

Pertanyaan

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  • [tex] \frac{pt}{pt + tr} = \frac{st}{qr } = \frac{ps}{ps + sq} \\ \\ pt = 12 - 4 \\ = 8cm \\ \\ \frac{8}{8 + 4} = \frac{10}{qr} \\ \frac{8}{12} = \frac{10}{qr} \\ 8qr = 10 \times 12 \: \: (perkalian \: silang) \\ 8qr = 120 \\ qr = 15cm \\ \\ \frac{st}{qr} = \frac{ps}{ps + sq} \\ \frac{10}{15} = \frac{ps}{ps + 6} \\ 15rs = 10(ps + 6) \\ 15ps = 10ps + 60 \\ 15ps - 10ps = 60 \\ 5ps = 60 \\ ps = 12cm [/tex]
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