berapakah besar i1,i2,i3?

Hambatan
R = R₁ + (1/R₂ ₃+ 1/R)⁻¹
R = 2 + (1/12 + 1/6)⁻¹
R = 6 ohm

Kuat arus induk
V = i R
3 = i • 6
i = ½ A ✓

i₁ : i₂ = 1/R₂ : 1/R₃
i₁ : i₂ = 1/12 : 1/6 = 1 : 2

i₁ = [1/(1+2)] × (½ A) = 1/6 A ✓
i₂ = [2/(1+2)] × (½ A) = 1/3 A ✓