2×-5y=-2. -3×+4y=-4 dengan mengunakan metode subtitusi tentukan himpunan penyelesaian dari sistem persamaan

2x = -2 + 5y
x = -1 + 2,5y

3x + 4y = -4
3(-1 + 2,5y) + 4y = -4
-3 + 7,5y + 4y = -4
11,5y = -1
y = -1/11,5
y = - 2/23
x = -1

x = -1 + 2,5y
x = -1 + 2,5(2/23)
x = -1 + 5/23
x = -18/23

2x - 5y = - 2
2x = 5y - 2
x = 5/2 y - 1

- 3x + 4y = - 4
- 3(5/2 y - 1) + 4y = - 4
- 15/2 y + 3 + 4y = - 4
- 15/2 y + 8/2 y = - 4 - 3
- 7/2 y = - 7
y = - 7 ÷ - 7/2
y = - 7 × - 2/7
y = 2

x = 5/2 . 2 - 1
x = 5 - 1
x = 4

hp = {4,2}