nilai x dari ......... [tex] \sqrt{ {8}^{x - 5} } = {4}^{4} + ^{2} [/tex]

√(8^(x-5) = 4^(x+2)
√(2^3)^(x-5) = (2^2)^(x+2)
√(2^)3x-15 = 2^(2x+4)
{ (2^)3x-15 }^1/2 = 2^(2x+4)
(2^)3/2x-15/2 = 2^(2x+4)
3/2x -15/2 = 2x + 4
3x -15 = 4x +8
3x -4x = 8 +15
-x = 23
x = -23