dik f(x)=2x-3 dan g(x)=x²+2x-3.Tentukan nilai (fog)(2) dan gof(3)

f(x) = 2x dan g(x) = x^2 +2x - 3
fog(2) = f { g(2) }
= f (2^2 + 2.2 -3)
= f (5)
= 2.5 - 3
= 7
gof(3) = g { f (3) }
= g (2.3 - 3)
= g (3)
= 3^2 + 2.3 -3
= 9 + 6 - 3
= 12