tolong dibantu f(x) = x+1 ------ 2x-1 f'(x) = ?

f(x) = (x+1)/(2x-1)
Misal:
u= x+1 maka u' = 1
v= 2x-1 maka v' = 2
f'(x) = (u' v - u v')/v^2 = (1(2x-1) - (x+1)2) / (2x-1)^2 = (2x-1 - 2x - 2) / (2x-1)^2 = -3/(2x-1)^2