Matematika

Pertanyaan

tolong guys nomer 6 dan 7
tolong guys nomer 6 dan 7

1 Jawaban

  • 6) x^5 - 32
    ----------------
    x - 2

    = x^5 - 2^5
    ----------------
    ( x - 2 )

    = (x - 2)^5
    ---------------
    ( x - 2 )

    = (x - 2)⁴

    7) f(x) = 5x³ - 4x² + 3x - 2
    3f(4) = 3 {5(4)³ - 4(3)² + 3(4) - 2}
    = 3 { (5 × 64) - (4 × 9) + 12 - 2}
    = 3 (320 - 36 + 12 - 2)
    = 3 × 294
    = 882
    2f(3) = 2 {5(3)³ - 4(3)² + 3(3) - 2}
    = 2 { (5 × 27) - (4 × 9) + 9 - 2}
    = 2 (135 - 36 + 9 - 2}
    = 2 × 106
    = 212
    3f(4) - 2f(3) = 882 - 212 = 670