Matematika

Pertanyaan

Beserta Caranyaa Kalo Bisa
Beserta Caranyaa Kalo Bisa

2 Jawaban

  • m^6 n^9 : (m⁴n³ × mn⁴) = m^6 n^9 : m^(4+1) n^(3+4) = m^6 n^9 : m^5 n^7 = m^(6-5) n^(9-7) = m¹n² atau mn²
  • m^6n^9 : (m^4n^3 × mn^4)
    = m^(6-(4+1)) n^(9-(3+4))
    = m^(6-5) n^(9-7)
    = mn^2