Bagilah bentuk pecahan-pecahan aljabar berikut : a.) m/3 dan 2m/6 b.) 2a/3b dan 4a/6b c.) 12mn/5pq dan 6nm/15qp d.) 2p²q/4mn² dan p²q/2mn² e.) 4m²n²/3p³q² dan m

a) m/3 ÷ 2m/6
= m/3 × 6/2m
= 2/2
= 1

b) 2a/3b ÷ 4a/6b
= 2a/3b × 6b/4a
= 2/2
= 1

c) 12mn/5pq ÷ 6nm/15qp
= 12mn/5pq × 15qp/6nm
= 2×3 / 1
= 6

d) 2p²q/4mn² ÷ p²q/2mn²
= 2p²q/4mn² × 2mn²/p²q
= 2/4
= ½

e) 4m²n²/3p³q² ÷ m²n/9p³q²
= 4m²n²/3p³q² × 9p³q²/m²n
= 4×3 / 1
= 12

Mapel       : Matematika
Kategori   : Aljabar
Kelas        : SMP / MTs kelas VII
Semester : Ganjil


Pembahasan:
Soal nomer a.
[tex]= \frac{m}{3} : \frac{2m}{6} [/tex]
[tex]= \frac{m}{3}.\frac{6}{2m} [/tex]
[tex]= \frac{3}{3}[/tex]
= 1

Soal nomer b
[tex]= \frac{2a}{3b} : \frac{4a}{6b} [/tex]
[tex]= \frac{2a}{3b}.\frac{6b}{4a} [/tex]
[tex]= \frac{2}{2}[/tex]
= 1

Soal nomer c
[tex]= \frac{12mn}{5pq} : \frac{6nm}{15qp} [/tex]
[tex]= \frac{12mn}{5qp}.\frac{15qp}{6nm} [/tex]
[tex]= \frac{6}{1}[/tex]
= 6

Soal nomer d
[tex]= \frac{2p^{2}q}{4mn^{2}} : \frac{p^{2}q}{2mn^{2}} [/tex]
[tex]= \frac{2p^{2}q}{4mn^{2}}.\frac{2mn^{2}}{p^{2}q} [/tex]
[tex]= \frac{2}{4}[/tex]
= ½

soal nomer e
[tex]= \frac{4m^{2}n^{2}}{3p^{3}q^{2}} : \frac{m^{2}n}{9p^{3}q^{2}} [/tex]
[tex]= \frac{4m^{2}n^{2}}{3p^{3}q^{2}}.\frac{9p^{3}q^{2}}{m^{2}n}[/tex]
[tex]= \frac{12}{1}[/tex]
= 12