3p - 2q = 6 dan 5p + 3q = 29 metode subtitusi

3p - 2q = 6
3p = 6 + 2q
p = 6 + 2q/3

Subtitusikan
5p + 3q = 29
5(6+2q/3) + 3q = 29
30 + 10q/3 + 3q = 29
30 + 10q + 9q = 29×3
30 + 19q = 87
19q = 87-30
19q = 57
q = 57/19
q = 3

Subtitusi lagi
p = 6 + 2q/3
p = 6 + 2(3)/3
p = 6 + 6/3
p = 12/3
p = 4

Himpunan penyelesaian {p, q} = {4,3}