suatu fungsi f(x)=x²-3 tentukan nilai dari f(-3) dan f(-5) tolong pakai cara ya.. makasih

Jawab :

1) f(x) = x² - 3
f(-3) = (-3)² - 3 = 9 - 3 = 6

2) f(x) = x² - 3
f(-5) = (-5)² - 3 = 25 - 3 = 22

[tex]f(x) = {x}^{2} - 3 \\ f( - 3) = { - 3}^{2} - 3 \\ = 9 - 3 = 6 \\ f( - 5) = { - 5}^{2} - 3 \\ = 25 - 3 = 22[/tex]