[tex] \frac{ {6a}^{2} + 23a + 20 }{ {4a }^{2} - 25} [/tex] tolong ya
Matematika
alya1012
Pertanyaan
[tex] \frac{ {6a}^{2} + 23a + 20 }{ {4a }^{2} - 25} [/tex]
tolong ya
1 Jawaban
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1. Jawaban dharmawan12
6a^2 + 23 a + 20
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4a^2 - 25
(3a + 4 ) ( 2a + 5 )
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(2a - 5 ) (2a + 5 )
3a + 4
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2a - 5