jika a=-3 b=1 c=-5 hitunglah 2a(a2 + 3b2 - 2c2)

2(-3) [(-3)²+3(1)²-2(-5)²]
-6[-9+3-(-2)(25)]
-6[-9+3-(-50)]
-6[-9+3+50]
-6[44]
-264

a = -3
b = 1
c = -5

2a(2a + 3b² - 2c²)
2(-3)(2(-3) + 3(1)² - 2(-5)²)
  -6 (-6 + 3 - 2(25))
  -6 ( -3 - 50)
  -6 ( -53)
     318