3 ( 2y - 3 )= 5 ( y- 2)

[tex]3(2y-3)=5(y-2) \\ 3 \times 2y- 3 \times 3 = 5 \times y - 5 \times 2 \\ 6y-9=5y -10 \\ 6y - 5y = -10 +9 \\ \therefore y=-1[/tex]

6y-9 = 5y-10
6y-5y = -10+9
y. = -1